Possible existence of bound nuclei beyond neutron drip lines driven by deformation
本站小编 Free考研考试/2022-01-01
Xiao-Tao He1, , Chen Wang1, , Kai-Yuan Zhang2, , Cai-Wan Shen3, , 1.College of Materials Science and Technology, Nanjing University of Aeronautics and Astronautics, Nanjing 210016, China 2.State Key Laboratory of Nuclear Physics and Technology, School of Physics, Peking University, Beijing 100871, China 3.School of Science, Huzhou University, Huzhou 313000, China Received Date:2021-06-10 Available Online:2021-10-15 Abstract:Based on the relativistic calculations of the nuclear masses in the transfermium region from No $ (Z = 102) $ to Ds $ (Z = 110) $ using the deformed relativistic Hartree-Bogoliubov theory in continuum (DRHBc), the possible existence of bound nuclei beyond the neutron drip lines is studied. The two-neutron and multi-neutron emission bound nuclei beyond the primary neutron drip line of $ N = 258 $ are predicted in $ Z = 106,108 $, and $ 110 $ isotopes. A detailed microscopic mechanism investigation reveals that nuclear deformation plays a vital role in the existence of bound nuclei beyond the drip line. Furthermore, not only the quadrupole deformation $ \beta_{2} $ but also the higher orders of deformation are indispensable in the reliable description of the phenomenon of reentrant binding.
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II.THEORETICAL FORMALISM AND NUMERICAL DETAILSThe details of the DRHBc theory can be found in Refs. [9, 22, 39, 40]. The DRHBc theory with a point-coupling density functional has been presented in Ref. [24]. For simplicity, we only briefly describe the main formalism here. The relativistic Hartree-Bogoliubov (RHB) equation is
which is solved in a Dirac Woods-Saxon basis [23]. $ E_{k} $ is the quasiparticle energy, and $ (U_{k} ,V_{k})^{\mathrm{T}} $ is the quasiparticle wave function. $ \lambda_{\tau} $ ($ \tau = n\ \mathrm{or}\ p $) is the Fermi energy. The pairing potential $ \Delta $ is
where $ \kappa(\boldsymbol{r}_{1},\boldsymbol{r}_{2}) $ is the pairing tensor, and $ V^{pp}(\boldsymbol{r}_{1},\boldsymbol{r}_{2}) $ is a density dependent force of zero-range
$ V_0 $ is the pairing strength, $ \rho_{\mathrm{sat}} $ is the saturation density of nuclear matter and $ \dfrac{1}{2}(1-P^{\sigma}) $ is the projector for the spin $ S = 0 $ component. The Dirac Hamiltonian $ h_{D} $ is expressed as
with $ S(\boldsymbol{r}) $ and $ V(\boldsymbol{r}) $ being the scalar and vector potentials, respectively. For an axially deformed nuclei with the reflection symmetric shape, the potential can be expanded in terms of Legendre polynomials,
The relativistic Hartree-Bogoliubov equations are solved in a spherical Dirac Woods-Saxon basis to obtain the wave functions. The total energy of a nucleus can be obtained as [7]
with A the mass number and $ \hat{\boldsymbol P} $ the total momentum for nucleus in the c.m. frame. The present calculations are carried out with the density functional PC-PK1. The numerical details are the same as those used in Ref. [24]. The Dirac Woods-Saxon basis is chosen with the box size $ R_{ \rm{box}} = 20 $ fm and the mesh size $ \Delta r = 0.1 $ fm. The numbers of states in the Dirac sea and Fermi sea are set to be the same. The energy cutoff for the Woods-Saxon basis is taken as $ E^{+}_{ \rm{cut}} = 300 $ MeV, and the angular momentum cutoff is $ J_{ \rm{max}} = 23/2\hbar $. The density-dependent zero-range pairing force is adopted, and the pairing strength is determined by the experimental odd-even differences in binding energies. For the particle-particle channel, with a pairing window of $ 100 $ MeV, the saturation density $ \rho_{ \rm{sat}} = 0.152 $ fm$ ^{-3} $, and pairing strength $ V_0 = -325.0 $ MeV fm$ ^3 $. The convergence check of the Legendre expansion has been performed [41], and $ \lambda_{ \rm{max}} = 10 $ is used in the present work.
IV.MICROSCOPIC MECHANISM ANALYSISWe take Ds isotopes near the neutron drip line as an example to reveal the microscopic mechanism of reentrant binding beyond the drip line. Table 1 shows the detailed results from $ ^{362} {\rm{Ds}}$ to $ ^{404} {\rm{Ds}}$. The single neutron energy levels of the nuclei around $ ^{368} {\rm{Ds}}$ are shown in Fig. 2. One can see that for the spherical nuclei $ ^{368} {\rm{Ds}}$, $ ^{370} {\rm{Ds}}$, and $ ^{372} {\rm{Ds}}$, a large shell gap appears for these three nuclei at $ N = 258 $, which indicates the nature of spherical shell closure. According to the two-neutron separation energies, $ ^{368} {\rm{Ds}}$ is a bound nucleus, whereas $ ^{370} {\rm{Ds}}$ and $ ^{372} {\rm{Ds}}$ are not. This is because the neutron Fermi surface of $ ^{368} {\rm{Ds}}$ is just at the $ N = 258 $ spherical shell. For the ground state, all the 258 neutrons occupy the single-particle levels below the continuum threshold (shown by the dot-dashed line in Fig. 2). For $ ^{370} {\rm{Ds}}$ ($ ^{372} {\rm{Ds}}$), there are two (four) neutrons mainly occupying the $ 1k_{15/2} $ orbital, which are just above the continuum threshold. Therefore, the Fermi energies of $ ^{370,372} {\rm{Ds}}$ are positive, and their two-neutron separation energies are negative, and thus, $ ^{370,372} {\rm{Ds}}$ are unbound against two-neutron emission. For $ ^{374} {\rm{Ds}}$, six more neutrons, in comparison with $ ^{368} {\rm{Ds}}$, lead to deformation of $ \beta_{2} = 0.064 $. Three deformed single-particle levels stemming from the spherical orbitals $ 2i_{13/2} $ and $ 1k_{15/2} $ drop, and their energies become negative. The increased deformation leads to a much smaller $ N = 258 $ shell gap as the neutron number N increases. For the ground state, the six neutrons mainly occupy the three levels just below the continuum threshold, and the Fermi energy becomes negative with a very small absolute value. However, $ ^{374} {\rm{Ds}}$ is still unbound against two-neutron emission due to the negative two-neutron separation energy, which can be explained by a loss of pairing energy. For $ ^{376} {\rm{Ds}}$, the deformation increases, five deformed single-particle levels drop below the continuum threshold, and there is no energy gap around the Fermi surface. The two-neutron separation energy is positive, and the Fermi energy is negative. $ ^{376} {\rm{Ds}}$ is bound against two-neutron emission but unbound against multi-neutron emission. $ ^{378} {\rm{Ds}}$ is very similar to $ ^{376} {\rm{Ds}}$. For the heavier isotopes up to $ ^{400} {\rm{Ds}}$, the deformation $ \beta_{2} $ keeps increasing, and more deformed single-particle levels stemming from the $ 2i_{13/2} $ and $ 1k_{15/2} $ orbitals drop below the continuum threshold. $ ^{380-400} {\rm{Ds}}$ are all bound nuclei. Therefore, we see that the nuclear deformation can strongly influence the single-particle levels and the shell structures. It plays a vital role in reentrant binding beyond the drip lines in the presence of shell effects at neutron closure $ (N = 258) $.
A
N
B/MeV
$ S_{2n} $/MeV
$ \lambda_{n} $/MeV
$ \beta_{2} $
$ Z=110 $ (Ds)
362
252
2284.175
3.311
?1.468
?0.084
364
254
2287.042
3.311
?1.570
?0.051
366
256
2290.220
3.178
?1.421
?0.034
368
258
2293.352
3.132
?0.834
0.000
370
260
2292.776
?0.576
0.255
0.000
372
262
2292.224
?0.552
0.237
0.000
374
264
2291.931
?0.293
?0.113
0.064
376
266
2292.448
0.517
?0.325
0.097
378
268
2293.115
0.667
?0.337
0.118
380
270
2293.724
0.609
?0.317
0.136
382
272
2294.359
0.635
?0.358
0.155
384
274
2295.126
0.767
?0.454
0.177
386
276
2296.139
1.013
?0.555
0.201
388
278
2297.258
1.119
?0.555
0.218
390
280
2298.299
1.041
?0.481
0.232
392
282
2299.146
0.847
?0.405
0.243
394
284
2299.886
0.741
?0.370
0.253
396
286
2300.566
0.679
?0.330
0.260
398
288
2301.156
0.590
?0.275
0.265
400
290
2301.593
0.437
?0.141
0.269
402
292
2301.674
0.081
0.008
0.273
404
294
2301.555
?0.119
0.071
0.277
Table1.Ground-state properties of Ds isotopes with $ 252\leqslant N\leqslant294 $ calculated using the DRHBc theory. The two-neutron unbound nuclei are underlined.
Figure2. (color?online)?Single-neutron energy levels in the canonical basis near the Fermi surface of Ds isotopes with $ 256\leqslant N\leqslant270 $. The neutron Fermi energy $ \lambda_{n} $ of each isotope is denoted by hollow stars.
As the existence of the bound nuclei beyond the drip line is affected strongly by the nuclear deformation, it is essential to investigate how strong the influence of the different orders of deformation is on this phenomenon. We perform the DRHBc constrained calculations at $ \beta_{2} = 0 $ and unconstrained calculations with the Legendre expansion truncation $ \lambda_{\mathrm{max}} = 2 $ (only including quadrupole deformation $ \beta_{2} $), $ \lambda_{\mathrm{max}} = 4 $ (including quadrupole and hexadecapole deformations $ \beta_{2} $ and $ \beta_{4} $), and $ \lambda_{\mathrm{max}} = 6 $ (including $ \beta_2 $, $ \beta_4 $, and $ \beta_6 $), respectively. The calculated total energies relative to that of $ ^{368} {\rm{Ds}}$$ (N = 258) $ as a function of the neutron number for $ ^{364-402} {\rm{Ds}}$ are presented in Fig. 3. One can see that for the calculations with $ \beta_{2} = 0 $, $ E-E_{N = 258} $ increases at $ N>258 $. No bound nuclei would exist beyond the drip line. For the calculation of $ \lambda_{\mathrm{max}} = 2 $, there are 4 unbound, 3 two-neutron emission bound while multi-neutron emission unbound, and 12 bound nuclei beyond the neutron drip line. Comparing with the result of $ \lambda_{\mathrm{max}} = 10 $, there is 1 additional two-neutron emission bound but multi-neutron emission unbound nucleus beyond the drip line. For the calculation of $ \lambda_{\mathrm{max}} = 4 $, except for the quantitive differences, the obtained bound nuclei are the same as those of the $ \lambda_{\mathrm{max}} = 10 $ calculation. For the calculations of $ \lambda_{\mathrm{max}} = 6 $, the results are very similar to those of $ \lambda_{\mathrm{max}} = 10 $, except that there is 1 additional bound nucleus obtained in the calculations with $ \lambda_{\mathrm{max}} = 6 $. It demonstrates clearly that the nuclear deformation is vital to the existence of the bound nuclei beyond the drip lines. Figure3. (color online) DRHBc calculated total energies relative to that of $ ^{358} {\rm{Ds}}$ (N = 258) under different expansion orders of deformation. The bound and unbound nuclei are denoted by the solid and open symbols, respectively. The nuclei that are bound against two-neutron emission while unbound against multi-neutron emission are denoted by the crossed open symbols.